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Re: (x + 2) (x – 3) vs x2 – x – 6 [#permalink]
sandy wrote:
Quantity A
Quantity B
\((x + 2) (x - 3)\)
\(x^2 - x - 6\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

My Answer is c
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Re: (x + 2) (x – 3) vs x2 – x – 6 [#permalink]
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Explanation

Terms in Quantity A:
\((x + 2)(x - 3) = x^2 - 3x + 2x - 6 = x^2 - x - 6\)

The two quantities are equal.
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Re: (x + 2)(x - 3) vs x2 - x - 6 [#permalink]
1
sandy wrote:
Quantity A
Quantity B
\((x + 2)(x - 3)\)
\(x^2 - x - 6\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


GIVEN:
QUANTITY A: (x + 2)(x - 3)
QUANTITY B: x² - x - 6

Use FOIL to expand and simplify Quantity A:
QUANTITY A: x² - x - 6
QUANTITY B: x² - x - 6

Answer: C

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Re: (x + 2) (x 3) vs x2 x 6 [#permalink]
1
Given that the Quantity A is a multiplication of two linear equations, and Quantity B is a quadratic, and also that the multiplication of the constant terms in the linear factors gives me -6 which is present in Quantity B, there is a high probability that FOILing the linear factors will give me Quantity B, and that is something that I will attempt.

\((x + 2)(x - 3)\)

\(x^2 - 3x + 2x -6\)

\(x^2 - x - 6\)

Quantity A = Quantity B

Answer is Choice C
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Re: (x + 2) (x 3) vs x2 x 6 [#permalink]
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