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Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
x^2 + y + 2w + 6x + 1 = -2 w = 3 – y/2
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01 Mar 2022, 04:00
01 Mar 2022, 04:00
1
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Question Stats:
73% (01:23) correct
26% (02:02) wrong based on 23 sessions
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\(x^2 + y + 2w + 6x + 1 = -2\)
\(w = 3 – \frac{y}{2}\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
\(w = 3 – \frac{y}{2}\)
Quantity A |
Quantity B |
x |
-1 |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
x^2 + y + 2w + 6x + 1 = -2 w = 3 – y/2
[#permalink]
01 Mar 2022, 06:53
01 Mar 2022, 06:53
1
Given, \(w = 3 - \frac{y}{2}\)
\(x^2 + y + 2w + 6x + 1 = -2\)
or, \(x^2 + + 2 (3 - \frac{y}{2}) + 6x +1 = -2\)
or, \(x^2 + y + 6 - y + 6x + 1 = -2\)
or, \(x^2 + 6 + 6x + 1 = -2\)
or,\( x^2 + 9 + 6x = 0\)
or, \(x^2 + 3x + 3x + 9 = 0\)
or, \(x(x +3) + 3(x + 3) = 0\)
or, \((x+3) (x+3) = 0\)
or, \((x+3)^2 = 0\)
or, \(x + 3 = 0\)
or, \(x = -3\)
Since, -3 < -1, B is the ans.
\(x^2 + y + 2w + 6x + 1 = -2\)
or, \(x^2 + + 2 (3 - \frac{y}{2}) + 6x +1 = -2\)
or, \(x^2 + y + 6 - y + 6x + 1 = -2\)
or, \(x^2 + 6 + 6x + 1 = -2\)
or,\( x^2 + 9 + 6x = 0\)
or, \(x^2 + 3x + 3x + 9 = 0\)
or, \(x(x +3) + 3(x + 3) = 0\)
or, \((x+3) (x+3) = 0\)
or, \((x+3)^2 = 0\)
or, \(x + 3 = 0\)
or, \(x = -3\)
Since, -3 < -1, B is the ans.
gmatclubot
x^2 + y + 2w + 6x + 1 = -2 w = 3 – y/2 [#permalink]
01 Mar 2022, 06:53
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