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(x^3 – y^3)(x^3 + y^3) =
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08 Feb 2021, 07:09
08 Feb 2021, 07:09
Expert Reply
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Question Stats:
70% (00:25) correct
30% (01:42) wrong based on 20 sessions
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\((x^3 – y^3)(x^3 + y^3) =\)
A. \(x^6 – y^6\)
B. \(x^6 + y^6\)
C. \(x^9 – y^9\)
D. \(x^9 + y^9\)
E. \(x^9 – 2x^3y^3 + y^9\)
Kudos for the right answer and explanation
A. \(x^6 – y^6\)
B. \(x^6 + y^6\)
C. \(x^9 – y^9\)
D. \(x^9 + y^9\)
E. \(x^9 – 2x^3y^3 + y^9\)
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: (x^3 – y^3)(x^3 + y^3) =
[#permalink]
08 Feb 2021, 07:52
08 Feb 2021, 07:52
2
Carcass wrote:
\((x^3 – y^3)(x^3 + y^3) =\)
A. \(x^6 – y^6\)
B. \(x^6 + y^6\)
C. \(x^9 – y^9\)
D. \(x^9 + y^9\)
E. \(x^9 – 2x^3y^3 + y^9\)
A. \(x^6 – y^6\)
B. \(x^6 + y^6\)
C. \(x^9 – y^9\)
D. \(x^9 + y^9\)
E. \(x^9 – 2x^3y^3 + y^9\)
We can see that this is a difference of squares that has been factored.
Key property: \((a + b)(a - b) = a^2 - b^2\)
So, \((x^3 – y^3)(x^3 + y^3) = (x^3)^2 – (y^3)^2\)
\(x^6 – y^6\)
Answer: A
Re: (x^3 y^3)(x^3 + y^3) =
[#permalink]
19 Jan 2024, 12:32
19 Jan 2024, 12:32
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
