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[m]x^4 – 8x^3 + ax^2 – bx + 16 = 0 has positive real roots.
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23 Sep 2021, 08:18
23 Sep 2021, 08:18
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26% (01:07) correct
73% (01:46) wrong based on 15 sessions
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\(x^4 – 8x^3 + ax^2 – bx + 16 = 0\) has positive real roots.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(b - a\) |
\(a - b\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
[m]x^4 – 8x^3 + ax^2 – bx + 16 = 0 has positive real roots.
[#permalink]
24 Sep 2021, 08:47
24 Sep 2021, 08:47
I didn't got a single clue on how to attempt this. If x^2 was highest power then I could have tackle it using the property b^2 - 4ac <0. But it has a highest power of 4.
Can someone please explain?
Can someone please explain?
Re: [m]x^4 – 8x^3 + ax^2 – bx + 16 = 0 has positive real roots.
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26 Sep 2021, 08:45
26 Sep 2021, 08:45
1
consider (x-2)^4
