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(x+40)^2 + (x-40)^2 [#permalink]
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I think the answer is A.
when I solved the them, I got A = 2x^2 + 3200 and B = -160x.
Now, If we take x = 0 then, A>B because it would be 3200 and B = 0
another case if we take x = -10000
then A would be 2*(-10000)^2 + 3200
and B would be 1600000
and A is still greater than B.
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Re: (x+40)^2 + (x-40)^2 [#permalink]
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if you test numbers such as 0,1,-1, or fractions such as 1/2 or -1/4 the result is different

D is the answer
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Re: (x+40)^2 + (x-40)^2 [#permalink]
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