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x and y are both integers : Quantitative Comparison Questions

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Re: x and y are both integers [#permalink]
Can someone please explain this?
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Re: x and y are both integers [#permalink]
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OE


As soon as you see variables and Quant Comp, make your set-up.

Plugging In is tricky here until you realize that one number must be negative. The 6 in Quantity B is also a clue. Try x = 3 andy = -2. y to the x power will be -8 and x to the y power will be 1/9, so these numbers work. xy = -6 so cross off choices (A) and (C). No matter what you plug in, y must be negative and x must be odd. Therefore xy will always be negative and 6 will always be greater. The answer is choice (B).
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Re: x and y are both integers [#permalink]
I'm a little confused, because 1/9 is not between -1 and 0. I understand the logic behind the rest of the question, but not that part. Do you mind explaining a bit more?


Carcass wrote:
OE


As soon as you see variables and Quant Comp, make your set-up.

Plugging In is tricky here until you realize that one number must be negative. The 6 in Quantity B is also a clue. Try x = 3 andy = -2. y to the x power will be -8 and x to the y power will be 1/9, so these numbers work. xy = -6 so cross off choices (A) and (C). No matter what you plug in, y must be negative and x must be odd. Therefore xy will always be negative and 6 will always be greater. The answer is choice (B).
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Re: x and y are both integers [#permalink]
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As Brent explained above x and y are both integers and NEGATIVE.

the OA assumes that x=3 and is not possible. That's why we end up with 1/8 which should be between -1 and 0 and is impossible.

NOT a good question after all
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Re: x and y are both integers [#permalink]
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