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Re: x and y are integers greater than 5. x is y percent of x^2 [#permalink]
grandPrep wrote:

Kindly explain why we can't do the following.

From

100 = xy

we can also write

100/y = x


Now if we plug the above value in Column A then we get

Col A----------------Col B
100/y----------------10

100/10----------------y

10----------------y


Since y>5 so answer should be D.

What's wrong here.


The problem with your solution is that it doesn't take into account the fact that x and y are integers greater than 5

So, once we know that 100 = xy (or 100/y = x), we can be certain that x and y both equal 10.
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x and y are integers greater than 5. x is y percent of x^2 [#permalink]
Quick question- should the answer here not be D?

If we sub in x=6, x^2 is 36. So, when considering that x is y% of x^2, y%= (6/36)*100=16.66%. This meets the criteria as x and y are over 5.
Here x is less than 10.

Let's consider the edge case of setting y to 5. Here, 0.05=x/x^2, solve for x=20
Here x is greater than 10.
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Re: x and y are integers greater than 5. x is y percent of x^2 [#permalink]
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nsrdr wrote:
Quick question- should the answer here not be D?

If we sub in x=6, x^2 is 36. So, when considering that x is y% of x^2, y%= (6/36)*100=16.66%. This meets the criteria as x and y are over 5.
Here x is less than 10.

Let's consider the edge case of setting y to 5. Here, 0.05=x/x^2, solve for x=20
Here x is greater than 10.


See above the calculations provided by Brent in his solution

Your calculations are wrong
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Re: x and y are integers greater than 5. x is y percent of x^2 [#permalink]
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