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x and y are positive integers such that x > y
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05 Jan 2020, 01:43
05 Jan 2020, 01:43
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x and y are positive integers such that \(x > y\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation[/m]
Quantity A |
Quantity B |
\(x^y\) |
\(y^x \) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation[/m]
Re: x and y are positive integers such that x > y
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05 Jan 2020, 04:18
05 Jan 2020, 04:18
1
Carcass wrote:
x and y are positive integers such that \(x > y\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation[/m]
Quantity A |
Quantity B |
\(x^y\) |
\(y^x \) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation[/m]
CASE I:
let x = 2 and y = 1
QTY A:: \(x^y\) = \(2^1 = 2\)
QTY B :: \(y^x \) = \(1^2 = 1\)
Therefore QTY A > QTY B
CASE II::
let x = 3 and y = 3
QTY A:: \(x^y\) =\( 4^3 = 64\)
QTY B :: \(y^x \) = \(3^4 = 81\)
Therefore QTY A < QTY B
Hence, Option D
Re: x and y are positive integers such that x > y
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14 Jan 2020, 13:06
14 Jan 2020, 13:06
1
pranab01 wrote:
Carcass wrote:
x and y are positive integers such that \(x > y\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation[/m]
Quantity A |
Quantity B |
\(x^y\) |
\(y^x \) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation[/m]
CASE I:
let x = 2 and y = 1
QTY A:: \(x^y\) = \(2^1 = 2\)
QTY B :: \(y^x \) = \(1^2 = 1\)
Therefore QTY A > QTY B
CASE II::
let x = 3 and y = 3
QTY A:: \(x^y\) =\( 4^3 = 64\)
QTY B :: \(y^x \) = \(3^4 = 81\)
Therefore QTY A < QTY B
Hence, Option D
The question tells that x>y so case II is not correct.
Although we can consider another set of values such as x=1 and y=100
Qty A: 1
Qty B: 100
therefore, answer D
