GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
x is a positive integer.
[#permalink]
19 Dec 2022, 14:54
19 Dec 2022, 14:54
Expert Reply
1
Bookmarks
00:00
Question Stats:
65% (01:53) correct
34% (02:00) wrong based on 32 sessions
Hide Show timer Statistics
x is a positive integer.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\( \frac{\frac{5x}{7}}{\frac{8}{2x+3}}\) |
\(\frac{x^2}{4 }+ \frac{8x}{7}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: x is a positive integer.
[#permalink]
22 Jan 2023, 10:03
22 Jan 2023, 10:03
Expert Reply
A can be written as
\(\frac{10x^2+15x}{56}=\)
B is \(\frac{7x^2+32x}{28}\)
making a common denominator
B is \(\frac{14x^2+64x}{56}\)
Clearly B is greater
\(\frac{10x^2+15x}{56}=\)
B is \(\frac{7x^2+32x}{28}\)
making a common denominator
B is \(\frac{14x^2+64x}{56}\)
Clearly B is greater
x is a positive integer.
[#permalink]
19 Jan 2024, 19:40
19 Jan 2024, 19:40
1
Quantity A
\(\dfrac{\frac{5x}{7}}{\frac{8}{2x+3}}\)
\(\frac{5x}{7} \times \frac{2x+3}{8}\)
\(\frac{10x^2+15x}{56}\)
Quantity B
\(\frac{x^2}{4} + \frac{8x}{7}\)
\(\frac{7x^2 + 32x}{28}\)
dividing both sides by 28
Quantity A = \(\frac{10x^2+15x}{2} = 5x^2 + 7.5x\)
Quantity B = \(7x^2 + 32x\)
Since \(x\) is a positive integer
Clearly Quantity B is greater
\(\dfrac{\frac{5x}{7}}{\frac{8}{2x+3}}\)
\(\frac{5x}{7} \times \frac{2x+3}{8}\)
\(\frac{10x^2+15x}{56}\)
Quantity B
\(\frac{x^2}{4} + \frac{8x}{7}\)
\(\frac{7x^2 + 32x}{28}\)
dividing both sides by 28
Quantity A = \(\frac{10x^2+15x}{2} = 5x^2 + 7.5x\)
Quantity B = \(7x^2 + 32x\)
Since \(x\) is a positive integer
Clearly Quantity B is greater
