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x^sqrt of y
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14 Sep 2023, 02:00
14 Sep 2023, 02:00
Expert Reply
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Question Stats:
62% (01:07) correct
37% (01:48) wrong based on 16 sessions
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\(x^{\sqrt{y}}=\sqrt[y]{x }\), where \(x>1\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
y |
1 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Re: x^sqrt of y
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22 Sep 2023, 08:17
22 Sep 2023, 08:17
1
Not sure this is the correct method, but this is what I did:
x^root y = y root x
x ^ y ^ 1/2 = x ^ 1/y
y^1/2 = 1/y
Test numbers:
y = 1
1 = 1
y = 4
2 = 1/4
y = 16
4 = 1/16
The only value for y that equals is 1. The answer choice is C.
x^root y = y root x
x ^ y ^ 1/2 = x ^ 1/y
y^1/2 = 1/y
Test numbers:
y = 1
1 = 1
y = 4
2 = 1/4
y = 16
4 = 1/16
The only value for y that equals is 1. The answer choice is C.
gmatclubot
Re: x^sqrt of y [#permalink]
22 Sep 2023, 08:17
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