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X= sum of the first 31 positive odd integers Y= sum of the first 30 po
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29 Jan 2026, 02:52
29 Jan 2026, 02:52
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71% (02:07) correct
28% (01:51) wrong based on 14 sessions
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X= sum of the first 31 positive odd integers
Y= sum of the first 30 positive even integers
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
Y= sum of the first 30 positive even integers
Quantity A |
Quantity B |
\(X-Y\) |
\(30\) |
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
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Re: X= sum of the first 31 positive odd integers Y= sum of the first 30 po
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16 Feb 2026, 00:50
16 Feb 2026, 00:50
First find the last value of X, we can do this by counting in sets of 5 to deduce a pattern, the first 5 odd integers are: {1, 3, 5, 7, 9}
Therefore, continuing this same sequence 6 times, our last sequence will be {51, 53, 55, 57, 59} to bring our total to 30 of the first 31, with 31 being {61}.
Now we do the same for Y, so the first 5 even integers (>0) are {2, 4, 6, 8, 10} and continuing the same pattern for #25-#30 we get: {52, 54, 56, 58, 60}
To easily find the same we can take the average value of Set X and Set Y respectively by following this format:
((last - first) / 2) * n, where n = total count
Set X: ((61 - 1) / 2) * 31, we receive 30 * 31 = 930
Set Y: ((60 - 2) / 2) * 30, we receive 29 * 30 = 870
930 - 870 = 60,
Therefore our answer is A
Therefore, continuing this same sequence 6 times, our last sequence will be {51, 53, 55, 57, 59} to bring our total to 30 of the first 31, with 31 being {61}.
Now we do the same for Y, so the first 5 even integers (>0) are {2, 4, 6, 8, 10} and continuing the same pattern for #25-#30 we get: {52, 54, 56, 58, 60}
To easily find the same we can take the average value of Set X and Set Y respectively by following this format:
((last - first) / 2) * n, where n = total count
Set X: ((61 - 1) / 2) * 31, we receive 30 * 31 = 930
Set Y: ((60 - 2) / 2) * 30, we receive 29 * 30 = 870
930 - 870 = 60,
Therefore our answer is A
gmatclubot
Re: X= sum of the first 31 positive odd integers Y= sum of the first 30 po [#permalink]
16 Feb 2026, 00:50
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