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x=-x+1/x
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28 Sep 2019, 09:57
28 Sep 2019, 09:57
Expert Reply
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Question Stats:
85% (00:40) correct
14% (00:40) wrong based on 49 sessions
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\(\blacksquare x=-x+\frac{1}{x}\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
Value of \(\blacksquare x\) if \(x =4\) |
Value of \(\blacksquare x\) if \(x =3\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: x=-x+1/x
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28 Sep 2019, 14:04
28 Sep 2019, 14:04
Carcass wrote:
\(\blacksquare x=-x+\frac{1}{x}\)
Quantity A |
Quantity B |
Value of \(\blacksquare x\) if \(x =4\) |
Value of \(\blacksquare x\) if \(x =3\) |
If \(x =4\), then \(\blacksquare x = \blacksquare 4 = -4 + \frac{1}{4}=-4 + 0.25=-3.75\)
If \(x =3\), then \(\blacksquare x = \blacksquare 3 = -3 + \frac{1}{3}≈-3 + 0.33≈-2.66\)
We get:
Quantity A: -3.75
Quantity B: -2.66
Answer: B
x=-x+1/x
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03 Jan 2024, 01:34
03 Jan 2024, 01:34
\(\blacksquare = -x + \frac{1}{x}\)
\(\text{Quantity A = if x = 4 then } \blacksquare x = -4 + \frac{1}{4} = -3\frac{3}{4}\)
\(\text{Quantity B = if x = 3 then } \blacksquare x = -3 + \frac{1}{3} = -2\frac{2}{3}\)
Therefore, Quantity B is always greater.
Answer is Choice B.
\(\text{Quantity A = if x = 4 then } \blacksquare x = -4 + \frac{1}{4} = -3\frac{3}{4}\)
\(\text{Quantity B = if x = 3 then } \blacksquare x = -3 + \frac{1}{3} = -2\frac{2}{3}\)
Therefore, Quantity B is always greater.
Answer is Choice B.
