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x + y = 16 and x y = 8

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x + y = 16 and x y = 8 [#permalink] New post   11 Jul 2022, 03:33
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\(x + y = 16\)
\(x − y = 8\)


Quantity A
Quantity B
\(x^2-y^2\)
\((x + y)(x + y)\)



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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Re: x + y = 16 and x y = 8 [#permalink] New post   19 Jul 2022, 01:57
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\(x^2 − y^2\) is the difference between two squares and factors to (x − y)(x + y). Since x + y = 16 and x − y = 8, column A then becomes 16 × 8 = 128. Column B is (x + y)(x + y) which is 16 × 16 = 256. Column B is greater.
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Re: x + y = 16 and x y = 8 [#permalink]
19 Jul 2022, 01:57
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