GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
x<y+1
[#permalink]
05 May 2025, 03:09
05 May 2025, 03:09
Expert Reply
1
Bookmarks
00:00
Question Stats:
66% (00:48) correct
33% (00:37) wrong based on 12 sessions
Hide Show timer Statistics
\(x<y+1\)
Quantity A |
Quantity B |
x |
y |
- Part of the project: GRE - Skill Builder Project II Edition - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
- Also replying to the unanswered questions
Re: x<y+1
[#permalink]
08 May 2025, 04:30
08 May 2025, 04:30
Expert Reply
Given: $\(x<y+1\)$
Compare:
- Quantity A: $x$
- Quantity B: $y$
Difficulty Level: Easy (Tests basic inequality understanding and case analysis.)
Step 1: Simplify the Inequality
- Rewrite $\(x<y+1\)$ as $\(x-y<1\)$.
- Interpretation: The difference between $x$ and $y$ is less than 1 , but no direct relationship is fixed.
Step 2: Test Possible Scenarios
1. $\(x>y\)$ :
- Example: $y=2, x=2.5$ (since $2.5<3$ ). Here, $x>y$.
2. $\(x=y\)$ :
- Example: $y=2, x=2$ (since $2<3$ ). Here, $x=y$.
3. $\(x<y\)$ :
- Example: $y=2, x=1$ (since $1<3$ ). Here, $x<y$.
Conclusion
- All three cases are possible under $\(x<y+1\)$.
- Answer: The relationship cannot be determined.
Compare:
- Quantity A: $x$
- Quantity B: $y$
Difficulty Level: Easy (Tests basic inequality understanding and case analysis.)
Step 1: Simplify the Inequality
- Rewrite $\(x<y+1\)$ as $\(x-y<1\)$.
- Interpretation: The difference between $x$ and $y$ is less than 1 , but no direct relationship is fixed.
Step 2: Test Possible Scenarios
1. $\(x>y\)$ :
- Example: $y=2, x=2.5$ (since $2.5<3$ ). Here, $x>y$.
2. $\(x=y\)$ :
- Example: $y=2, x=2$ (since $2<3$ ). Here, $x=y$.
3. $\(x<y\)$ :
- Example: $y=2, x=1$ (since $1<3$ ). Here, $x<y$.
Conclusion
- All three cases are possible under $\(x<y+1\)$.
- Answer: The relationship cannot be determined.
gmatclubot
Re: x<y+1 [#permalink]
08 May 2025, 04:30
Moderators:
