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x<y, x^2+y^2
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Updated on: 26 Aug 2021, 23:09
1
00:00
Question Stats:
66% (01:32) correct
33% (00:47) wrong based on 24 sessions
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timer Statistics
x<y
Quantity A
Quantity B
\(x^2+y^2\)
2xy
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
There's actually a perfect square hiding in this question.
Let's start by using matching operations (my favorite Quantitative Comparison strategy)
Subtract \(2xy\) from both quantities to get: Quantity A: \(x^2-2xy+y^2\) Quantity B: 0
Factor Quantity A to get: Quantity A: \((x-y)^2\) Quantity B: 0
Since \(x<y\), we know that \(x - y\) does not equal 0, which means \((x-y)^2\) must be POSITIVE. So we have: Quantity A: Some positive number Quantity B: 0
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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