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x, y, z, and m are positive integers.
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11 May 2022, 01:43
11 May 2022, 01:43
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x, y, z, and m are positive integers.
\(x=\frac{2}{5}m\) and \(y=\frac{5}{3}m\) and \(z=\frac{9}{10}y\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
\(x=\frac{2}{5}m\) and \(y=\frac{5}{3}m\) and \(z=\frac{9}{10}y\)
Quantity A |
Quantity B |
x |
z |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE Quantitative Comparison & Problem Solving Challenge
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
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Re: x, y, z, and m are positive integers.
[#permalink]
11 May 2022, 06:37
11 May 2022, 06:37
1
Carcass wrote:
x, y, z, and m are positive integers.
\(x=\frac{2}{5}m\) and \(y=\frac{5}{3}m\) and \(z=\frac{9}{10}y\)
\(x=\frac{2}{5}m\) and \(y=\frac{5}{3}m\) and \(z=\frac{9}{10}y\)
Quantity A |
Quantity B |
x |
z |
Take: \(z=\frac{9}{10}y\)
Replace \(y\) with \(\frac{5}{3}m\) to get: \(z=(\frac{9}{10})(\frac{5}{3})m\)
Simplify: \(z=(\frac{3}{2})m\)
So we have:
QUANTITY A: \((\frac{2}{5})m\)
QUANTITY B: \((\frac{3}{2})m\)
Since \(m\) is positive we can safely divide both quantities by \(m\) to get:
QUANTITY A: \(\frac{2}{5}\)
QUANTITY B: \(\frac{3}{2}\)
Answer: B
gmatclubot
Re: x, y, z, and m are positive integers. [#permalink]
11 May 2022, 06:37
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