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x < y < z and y - x > 7, where x is an even integer and y and z are

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KarunMendiratta
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x < y < z and y - x > 7, where x is an even integer and y and z are [#permalink] New post   05 Aug 2021, 05:57
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x < y < z and y - x > 7, where x is an even integer and y and z are odd integers.

Quantity A
Quantity B
Least possible value of z - x
10


A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
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A
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motion2020
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Re: x < y < z and y - x > 7, where x is an even integer and y and z are [#permalink] New post   05 Aug 2021, 08:05
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by manipulating and comparing two quantities, the answer is clearly A as \(z-x>10\)
KarunMendiratta wrote:
x < y < z and y - x > 7, where x is an even integer and y and z are odd integers.

Quantity A
Quantity B
Least possible value of z - x
10


A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
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nikarora909
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Re: x < y < z and y - x > 7, where x is an even integer and y and z are [#permalink] New post   06 Aug 2021, 23:34
the smallest value of x is 2. This gives the smallest value of y as 11 (not 9). Hence Smallest z is 13. 13-2>10. A is right.
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void
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Re: x < y < z and y - x > 7, where x is an even integer and y and z are [#permalink] New post   08 Aug 2021, 00:08
nikarora909 wrote:
the smallest value of x is 2. This gives the smallest value of y as 11 (not 9). Hence Smallest z is 13. 13-2>10. A is right.

why not y=9....explain it please.
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Re: x < y < z and y - x > 7, where x is an even integer and y and z are [#permalink] New post   08 Aug 2021, 00:17
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void wrote:
nikarora909 wrote:
the smallest value of x is 2. This gives the smallest value of y as 11 (not 9). Hence Smallest z is 13. 13-2>10. A is right.

why not y=9....explain it please.



if y=9, y-x = 7, not >7. So y#9. Thus, y is 11.
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Re: x < y < z and y - x > 7, where x is an even integer and y and z are [#permalink]
08 Aug 2021, 00:17
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