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Re: xyz > 0 and y>0 [#permalink]
1
There is a typo in the question.

Zero should not be a part of the A Term.
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Re: xyz > 0 and y>0 [#permalink]
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avnishkanungo wrote:
There is a typo in the question.

Zero should not be a part of the A Term.


Fixed the typo

Thak you
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Re: xyz > 0 and y>0 [#permalink]
what if both x and z is negative, xyz would still be positive, and the above expression can be negative...,
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xyz > 0 and y>0 [#permalink]
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\(xyz > 0\) and \(y > 0\)

QA \(xy^2z^3 \)

QB zero

Now both in the stem and in QA y is always positive so we can disregard y for now whatever is the value of y

we left with x and z that we do know >0

Now to have xz>0 both are positive or both are negative

if both negative and y^3 will be alwayspositive but multiplied negative x and negative z they will become positive ANDDDD y is positive and QA is positive

if xz>0 are both positive, then y is always positive and QA will be positive

A>B

A is the answer
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Re: xyz > 0 and y>0 [#permalink]
ahh yes, I missed that part, thank you for the explanation :-)
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