There is a typo in the question.

Zero should not be a part of the A Term.

Fixed the typo

Thak you

what if both x and z is negative, xyz would still be positive, and the above expression can be negative...,

$xyz > 0$ and $y > 0$

QA $xy^2z^3$

QB zero

Now both in the stem and in QA y is always positive so we can disregard y for now whatever is the value of y

we left with x and z that we do know >0

Now to have xz>0 both are positive or both are negative

if both negative and y^3 will be alwayspositive but multiplied negative x and negative z they will become positive ANDDDD y is positive and QA is positive

if xz>0 are both positive, then y is always positive and QA will be positive

A>B

A is the answer

ahh yes, I missed that part, thank you for the explanation