Last visit was: 26 Dec 2024, 11:28 It is currently 26 Dec 2024, 11:28
Decision Tracker
My Rewards
New comers' posts
New posts
Unanswered

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Go to My Error Log Learn more
Close

Request Expert Reply

Confirm Cancel
PREVIOUS TOPIC
NEXT TOPIC

z*10^k=6*10^m

Tags :
Find Similar Topics  About  Add a Tag

Show Tags
Hide Tags

User avatar
D
Carcass
Verbal Expert
Joined: 18 Apr 2015
Posts: 30510
Own Kudos [?]: 36867 [1]
Given Kudos: 26109
Send PM
z*10^k=6*10^m [#permalink] New post   06 Nov 2019, 09:29
Expert Reply
1
Bookmarks
00:00

Question Stats:

83% (00:48) correct 16% (00:36) wrong based on 81 sessions

Hide Show timer Statistics

\(z \times 10^k=6 \times 10^m\)


\(m=k+2\)


Quantity A
Quantity B
\(z\)
\(60\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation
ShowHide Answer
Official Answer
A
avatar
colinmavlon
Intern
Intern
Joined: 04 Nov 2019
Posts: 5
Own Kudos [?]: 5 [0]
Given Kudos: 7
Send PM
Re: z*10^k=6*10^m [#permalink] New post   06 Nov 2019, 09:44
1
We are given z*10^k=6*10^m

substituting k+1 for m

we have z*10^k=6*10^(k+2)

dividing both sides by 10

z=(6*10^(k+2))/10^k

reminder x^y/x^z equals x^(y-z)

so, we have z=6*10^(k+2-K)

z=6*100 which is higher than 60
User avatar
P
GreenlightTestPrep
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12238 [0]
Given Kudos: 136
Send PM

Top Member of the Month
z*10^k=6*10^m [#permalink] New post   06 Nov 2019, 12:40
2
Carcass wrote:
\(z \times 10^k=6 \times 10^m\)


\(m=k+2\)


Quantity A
Quantity B
\(z\)
\(60\)



GIVEN: If \(m=k+2\), then we know that \(m-k=2\)
We'll use this information shortly!


GIVEN: \(z \times 10^k=6 \times 10^m\)

Divide both sides by \(10^k\) to get: \(z=\frac{6 \times 10^m}{10^k}\)

Apply Quotient Law to get: \(z=6 \times 10^{m-k}\)

Replace \(m-k\) with \(2\) to get: \(z=6 \times 10^2\)

Simplify: \(z = 600\)

We get:
QUANTITY A: 600
QUANTITY A: 60

Answer: A

RELATED VIDEO
avatar
G
GR3A
Manager
Manager
Joined: 02 Sep 2019
Posts: 181
Own Kudos [?]: 144 [1]
Given Kudos: 94
Concentration: Finance
GRE 1: Q151 V148
GPA: 3.14
Send PM
Re: z*10^k=6*10^m [#permalink] New post   18 Jun 2020, 15:34
1
I did it like differently

z*10^k= 6*10^k*10^2
Divide both sides by 10^k
z=6*10^2 =z=600
A is bigger.
User avatar
bumpbot
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5091
Own Kudos [?]: 76 [0]
Given Kudos: 0
Send PM
Re: z*10^k=6*10^m [#permalink] New post   12 Jun 2022, 16:44
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
gmatclubot
Re: z*10^k=6*10^m [#permalink]
12 Jun 2022, 16:44
Moderators:
adewale223
GRE Instructor
88 posts
bronaugust
GRE Forum Moderator
37 posts
BrushMyQuant
Moderator
1115 posts
VibhuAnurag
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Main navigation

Partners

GRE Resources

www.ets.org/gre | About | Terms and Conditions and Privacy Policy | Prep Club for GRE Rules | Contact