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SherpaPrep received 3 Kudos for post Re: f(x) = 4x^2 + 28x + 49 for all x.

GiverPostDate
arjunbirRe: f(x) = 4x^2 + 28x + 49 for all x30-Jun-2021
RCDMCRe: f(x) = 4x^2 + 28x + 49 for all x27-Mar-2019
CarcassRe: f(x) = 4x^2 + 28x + 49 for all x03-Feb-2018

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