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GRE Question of the Day (January 10)Math \({A=\frac{{PId^2}}{{x}}}\) If the formula above gives the area A of a circular region in terms of its diameter d, then x= (A) \({\frac{{1}}{{4}}}\) (B) \({\frac{{1}}{{2}}}\) (C) 1 (D) 2 (E) 4 Question Discussion & Explanation |
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