|
GRE Question of the Day (March 29th) |
||
GRE Question of the Day (March 29th)
Math
\({x \neq 0}\)
\({\frac{{3}}{{x}}+\frac{{1}}{{4}}=\frac{{1}}{{2x}}}\)
|
Quantity A
|
Quantity B
|
|
\({x}\)
|
\({-5}\)
|
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Correct Answer - B - (click and drag your mouse to see the answer)
Latest in Blog
Aug 20Recent Comments
[0] Comments to this Article