GRE Question of the Day (January 24th)

Math

\({\frac{{1}}{{x^3}},\frac{{1}}{{x^2}},\frac{{1}}{{x}},x,x^2,x^3}\) If \({-1<x<0}\) , what is the median for the six numbers in the list above ? A. \({\frac{{1}}{{x}}}\) B. \({x^2}\) C. \({\frac{{x^2(x+1)}}{{2}}}\) D. \({\frac{{x(x^2+1)}}{{2}}}\) E. \({\frac{{x^2+1}}{{2x}}}\)   Correct Answer - D  - (click and drag your mouse to see the answer) Question Discussion & Explanation