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0 < k < n < k + 2
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Updated on: 18 Aug 2020, 15:51
Updated on: 18 Aug 2020, 15:51
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\(0 < k < n < k + 2\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(n\) |
\(k+1\) |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
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0 < k < n < k + 2
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30 Jan 2020, 07:19
30 Jan 2020, 07:19
goblobdo wrote:
0 < k < n < k + 2
Quantity A:
n
Quantity B:
k + 1
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A:
n
Quantity B:
k + 1
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
First notice that \(0 < k < k+1 < k+2\)
However, when we try to add the n to this inequality, we can't tell where it goes.
It COULD be the case that we have: \(0 < k < n < k+1 < k+2\)
OR
It COULD be the case that we have: \(0 < k < k+1 < n < k+2\)
This certainly suggests that the correct answer is D.
However, let's be sure and find some possible values to test.
case i: Since n is an integer, and k is not an integer and since \(0 < k < n < k + 2\), one possible pair of values is \(n=3\) and \(k=1.5\)
We get:
Quantity A: n = 3
Quantity B: k + 1 = 1.5 + 1 = 2.5
In this case, Quantity A is greater
case ii: Another possible pair of values is \(n=2\) and \(k=1.5\)
We get:
Quantity A: n = 2
Quantity B: k + 1 = 1.5 + 1 = 2.5
In this case, Quantity B is greater
Answer: D
Cheers.
Brent
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