Carcass wrote:
4, m, 5, 9, 3, n
The arithmetic mean of the above sequence of numbers is 4. If m and n are non-negative integers and m > n, what is the median number in the list?
(A) 3
(B) 3.5
(C) 4
(D) 4.5
(E) Cannot be determined
The arithmetic mean of the list of numbers above is 4. So, (4 + m + 5 + 9 + 3 + n)/6 = 4
Multiply both sides by 6 to get: 4 + m + 5 + 9 + 3 + n = 24
Simplify: 21 + m + n = 24
Subtract 21 from both sides to get:
m + n = 3If m and n are non-negative integers and m > n, what is the median number in the list? Since
m + n = 3, there are only two possible cases:
Case i: n = 0 and m = 3, in which case our list becomes {4, 3, 5, 9, 3, 0 }
Median = 3.5.Case ii: n = 1 and m = 2, in which case our list becomes {4, 2, 5, 9, 3, 1 }
Median = 3.5.In both possible cases, the median equals 3.5
Answer: B