Carcass wrote:
A ball drops from a certain height. The height it will reach after rebounding from the floor is 80 percent of the previous height. The total travel is 3,104cm when it touches the floor on the third time. What is the value of the original height, in cm?
A. 400cm
B. 500cm
C. 600cm
D. 700cm
E. 800cm
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITIONGRE - Math Book Let x be the ball's original heightSo, x = distance of the ball's first DROP
And 0.8x = distance of the ball's first RISE
0.8x = distance of the ball's second DROP
(0.8)(0.8x) = distance of the ball's second RISE
(0.8)(0.8x) = distance of the ball's third DROP
At this point, the ball touches the ground for the third time.
So, the TOTAL distance = x + 0.8x + 0.8x + (0.8)(0.8x) + (0.8)(0.8x) = 3104 cm
Simplify: x + 0.8x + 0.8x + 0.64x + 0.64x = 3104 cm
Simplify: 3.88x = 3104
Solve: x = 800
Answer: E