Carcass wrote:
A bar is creating a new signature drink. There are five possible alcoholic ingredients in the drink: rum, vodka, gin, peach schnapps, or whiskey. There are five possible non-alcoholic ingredients: cranberry juice, orange juice, pineapple juice, lime juice, or lemon juice. If the bar uses two alcoholic ingredients and two non-alcoholic ingredients, how many different drinks are possible?
A. 25
B. 50
C. 75
D. 100
E. 3600
Take the task of making a drink and break it into
stages.
Stage 1: Select two alcoholic ingredients for the drink
Since the order in which we select the ingredients does not matter, we can use combinations.
We can select 2 ingredients from 5 ingredients in 5C2 ways (10 ways)
So, we can complete stage 1 in
10 ways
If anyone is interested, we have a video on calculating combinations (like 5C2) in your head (see below)
Stage 2: Select two non-alcoholic ingredients for the drink
We'll use combinations again.
We can select 2 ingredients from 5 ingredients in 5C2 ways (10 ways)
So, we can complete stage 2 in
10 ways
By the Fundamental Counting Principle (FCP), we can complete the 2 stages (and thus create a drink) in
(10)(10) ways (100 ways)
Answer: D
Note: the FCP can be used to solve the MAJORITY of counting questions on the GRE, so be sure to learn it
RELATED VIDEO
[youtube]https://www.youtube.com/watch?v=Kj-Mv8VlipM[/youtube