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Re: A certain company has 18 equally qualified applicants for 4 open posit
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27 Feb 2023, 02:13
This is a combination problem, which involves choosing a certain number of objects from a set without regard to the order in which they are chosen. The formula for combinations is:
n C r = n! / r!(n - r)!
where n is the total number of objects, and r is the number of objects being chosen.
In this problem, there are 18 applicants and 4 open positions, and we want to know how many different groups of 4 applicants can be chosen. So we have:
n = 18
r = 4
Using the combination formula, we get:
18 C 4 = 18! / 4!(18 - 4)!
= (18 x 17 x 16 x 15) / (4 x 3 x 2 x 1)
= 3060
Therefore, there are 3,060 different groups of 4 applicants that can be chosen by the company to fill the positions if the order of selection does not matter. The answer is (E).