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Joined: 20 Feb 2017
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A certain research group plans to create computer models of x% of a li
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23 May 2021, 23:40
23 May 2021, 23:40
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A certain research group plans to create computer models of x% of a list of 10,000 bacterial species known to inhabit the human body. After a budget cut, the group finds it must reduce this selection by (x − 5)%. In terms of x, how many species of bacteria will the group be able to model?
A. x*x – 5x
B. (x)(105 – x)
C. (100)(105 – x)
D. (100)(95 – x)
E. (x-5)/100
A. x*x – 5x
B. (x)(105 – x)
C. (100)(105 – x)
D. (100)(95 – x)
E. (x-5)/100
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Re: A certain research group plans to create computer models of x% of a li
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24 May 2021, 02:00
24 May 2021, 02:00
2
GeminiHeat wrote:
A certain research group plans to create computer models of x% of a list of 10,000 bacterial species known to inhabit the human body. After a budget cut, the group finds it must reduce this selection by (x − 5)%. In terms of x, how many species of bacteria will the group be able to model?
A. x*x – 5x
B. (x)(105 – x)
C. (100)(105 – x)
D. (100)(95 – x)
E. (x-5)/100
A. x*x – 5x
B. (x)(105 – x)
C. (100)(105 – x)
D. (100)(95 – x)
E. (x-5)/100
let x be 10
so the model will be created for 1000 species
now the selection is reduced by (x - 5)% i.e. 5%
so the model will now be created for 5% of 1000 = 50 species
Total species that can be modelled = 1000 - 50 = 950
A. \(x^2 – 5x\)
\(10^2 - 5(10) = 50\)
B. \(x(105 – x)\)
\(10(105 - 10) = 950\)
C. \(100(105 – x)\)
\(100(105 - 10) = 9500\)
D. \(100(95 – x)\)
\(100(95 - 10) = 8500\)
E. \(\frac{(x - 5)}{100}\)
\(\frac{(10 - 5)}{100} = 0.05\)
Hence, option B
Alternate Approach:
initially model will be created for x% of 10000 = 100x
Later, the model will be created for (x - 5)% of 100x = x(x - 5)
Finally the model will be created for 100x - x(x - 5) = x[100 - x + 5] = x[105 - x] species
gmatclubot
Re: A certain research group plans to create computer models of x% of a li [#permalink]
24 May 2021, 02:00
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