Carcass wrote:
A certain road trip was completed in two parts interrupted by an hour-long lunch break. During the first portion of the trip the average speed was 55 miles per hour and the average speed during the second part of the trip was 63 miles per hour. If the trip was 480 miles long and took a total of 8 hours (excluding the time stopped for lunch) then which of the following is the amount of time spent driving before the lunch break?
A) 2
B) 3
C) 4
D) 5
E) 6
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITIONGRE - Math BookLet's start with a
word equation(
distance traveled during FIRST part of trip) + (
distance traveled during SECOND part of trip) = 480 miles
Let
t = time spend on FIRST part of trip (in hours)
So,
8-t = time spend on SECOND part of trip (since the ENTIRE driving time was 8 hour)
Distance = (speed)(time)So, we can write: (
55)(
t ) + (
63)(
8 - t) = 480
Expand:
55t + (
504 - 63t) = 480
Simplify: -8t + 504 = 480
Subtract 504 from both sides: -8t = -24
Solve: t = 3
Answer: B