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A chord AB of a circle subtends an angle of 120° at the cent
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Updated on: 14 Jul 2020, 01:18
Updated on: 14 Jul 2020, 01:18
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Question Stats:
85% (01:23) correct
15% (01:43) wrong based on 20 sessions
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circle.png [ 3.57 KiB | Viewed 1337 times ]
A chord AB of a circle subtends an angle of 120° at the centre O. If the radius of the circle is 2. What is the area of the triangle AOB?
A. 1
B. √3/2
C. √2
D. √3
E. Cannot be determined
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Attachment:
circle.png [ 3.57 KiB | Viewed 1337 times ]
Re: A chord AB of a circle subtends an angle of 120° at the cent
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14 Jul 2020, 01:14
14 Jul 2020, 01:14
1
OA is missing
Re: A chord AB of a circle subtends an angle of 120° at the cent
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14 Jul 2020, 16:35
14 Jul 2020, 16:35
1
I solved it by drawing perpendicular in between and it became 30-60-90 triangle.
x : x* sqrt3: 2x
we know that x=2
if i compare 2x=2, i get x=1 and I get correct answer of area of triangle
if i compare x* sqrt3 = 2, i get x=2/sqrt3, which is incorrect
Can anyone tell me, do we always have to compare value of any side with hypotenuse? i.e. 2x here
x : x* sqrt3: 2x
we know that x=2
if i compare 2x=2, i get x=1 and I get correct answer of area of triangle
if i compare x* sqrt3 = 2, i get x=2/sqrt3, which is incorrect
Can anyone tell me, do we always have to compare value of any side with hypotenuse? i.e. 2x here
