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A department consists of 12 workers, 5 temporary workers and 7 permane
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08 Apr 2022, 06:27
08 Apr 2022, 06:27
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A department consists of 12 workers, 5 temporary workers and 7 permanent workers. Among the 5 temporary workers, four are full-time and one is part-time. Among the 7 permanent workers, five are full-time and two are part-time. If one of the workers in the department is selected at random, what is the probability that the worker is a part-time worker, given that the worker is a permanent worker?
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{5}\)
(C) \(\frac{1}{6}\)
(D) \(\frac{2}{7}\)
(E) \(\frac{7}{12}\)
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{5}\)
(C) \(\frac{1}{6}\)
(D) \(\frac{2}{7}\)
(E) \(\frac{7}{12}\)
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Re: A department consists of 12 workers, 5 temporary workers and 7 permane
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08 Apr 2022, 06:35
08 Apr 2022, 06:35
1
Carcass wrote:
A department consists of 12 workers, 5 temporary workers and 7 permanent workers. Among the 5 temporary workers, four are full-time and one is part-time. Among the 7 permanent workers, five are full-time and two are part-time. If one of the workers in the department is selected at random, what is the probability that the worker is a part-time worker, given that the worker is a permanent worker?
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{5}\)
(C) \(\frac{1}{6}\)
(D) \(\frac{2}{7}\)
(E) \(\frac{7}{12}\)
(A) \(\frac{1}{4}\)
(B) \(\frac{1}{5}\)
(C) \(\frac{1}{6}\)
(D) \(\frac{2}{7}\)
(E) \(\frac{7}{12}\)
There are 7 permanent workers, 2 of whom are part-time.
So, if it's given that the worker is a permanent worker, then we're talking about 0ne of the seven permanent workers in the department.
So, P(the permanent worker is part time) = 2/7
Answer: D
gmatclubot
Re: A department consists of 12 workers, 5 temporary workers and 7 permane [#permalink]
08 Apr 2022, 06:35
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