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A function f(x) is defined for all real numbers as f(x) = (x
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14 May 2019, 01:10
14 May 2019, 01:10
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80% (00:47) correct
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A function f(x) is defined for all real numbers as f(x) = (x – 1)(x – 2)(x – 3)(x – 4)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
f(2.5) |
f(3.5) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Joined: 13 May 2019
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Posts: 186
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Location: United States
GMAT 1: 770 Q51 V44
GRE 1: Q169 V168
WE:Education (Education)
Re: A function f(x) is defined for all real numbers as f(x) = (x
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14 May 2019, 13:45
14 May 2019, 13:45
3
Expert Reply
With GRE Quantitative Comparisons look for savvy methods for comparison to avoid unnecessary calculation. In this case note the number of negative values created in each quantity.
Now for Quantity A: x - 1 and x - 2 are each > 0 | x - 3 and x - 4 are each < 0 --> Positive x Positive x Negative x Negative will result in a product > 0
Now for Quantity B: x - 1 is the only value > 0 --> Positive x Negative x Negative x Negative will result in a product < 0
Therefore, Quantity A will always be greater and the correct choice is A.
Quote:
A function f(x) is defined for all real numbers as f(x) = (x – 1)(x – 2)(x – 3)(x – 4)
Quantity A |
Quantity B |
f(2.5) |
f(3.5) |
Now for Quantity A: x - 1 and x - 2 are each > 0 | x - 3 and x - 4 are each < 0 --> Positive x Positive x Negative x Negative will result in a product > 0
Now for Quantity B: x - 1 is the only value > 0 --> Positive x Negative x Negative x Negative will result in a product < 0
Therefore, Quantity A will always be greater and the correct choice is A.
Re: A function f(x) is defined for all real numbers as f(x) = (x
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27 Jul 2019, 13:36
27 Jul 2019, 13:36
MyGuruStefan wrote:
With GRE Quantitative Comparisons look for savvy methods for comparison to avoid unnecessary calculation. In this case note the number of negative values created in each quantity.
Now for Quantity A: x - 1 and x - 2 are each > 0 | x - 3 and x - 4 are each < 0 --> Positive x Positive x Negative x Negative will result in a product > 0
Now for Quantity B: x - 1 is the only value > 0 --> Positive x Negative x Negative x Negative will result in a product < 0
Therefore, Quantity A will always be greater and the correct choice is A.
Quote:
A function f(x) is defined for all real numbers as f(x) = (x – 1)(x – 2)(x – 3)(x – 4)
Quantity A |
Quantity B |
f(2.5) |
f(3.5) |
Now for Quantity A: x - 1 and x - 2 are each > 0 | x - 3 and x - 4 are each < 0 --> Positive x Positive x Negative x Negative will result in a product > 0
Now for Quantity B: x - 1 is the only value > 0 --> Positive x Negative x Negative x Negative will result in a product < 0
Therefore, Quantity A will always be greater and the correct choice is A.
In quantity B, x-1, x-2 and x-3 all are positive, only x-4 is negative.
