Asif123 wrote:
A garment order consists of jackets costing $36 each and shirts costing $26 each. If the total cost of the order is $1,200, and if the average (arithmetic mean) cost per garment is $30, how many more shirts than jackets are in the order?
(A) 32 (B) 22 (C) 18 (D) 13 (E) 8
Let’s denote number of jackets as J and number of shirts as S.
Then we get two equations:
Total order cost is: 36J + 26S = 1 200
The average cost is: 1200 / (J +S) = 30 which is equivalent to 30J + 30S = 1 200
36J + 26S = 30J + 30S
6J = 4S
Substitute into total order cost equation: 24S + 26S = 1 20. Hence, S = 24 and J which 2/3 of S is equal to 16.
S > J by 8.