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A grocer buys apples at the regular price of 38 cents per pound.
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10 May 2021, 21:30
10 May 2021, 21:30
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A grocer buys apples at the regular price of 38 cents per pound.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
The amount saved by the grocer on a purchase of 100 pounds of apples if the price per pound is x cents less than the regular price |
The additional amount paid by the grocer on a purchase of 100 pounds of apples if the price per pound is x cents more than the regular price |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: A grocer buys apples at the regular price of 38 cents per pound.
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11 May 2021, 00:56
11 May 2021, 00:56
1
Carcass wrote:
A grocer buys apples at the regular price of 38 cents per pound.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The amount saved by the grocer on a purchase of 100 pounds of apples if the price per pound is x cents less than the regular price |
The additional amount paid by the grocer on a purchase of 100 pounds of apples if the price per pound is x cents more than the regular price |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Let \(x = 10\)
Cost of 100 apples at regular price = \(3800\) cents
Cost of 100 apples at discounted price = \(3800(0.90) = 3420\) cents
Cost of 100 apples at increased price = \(3800(1.10) = 4180\) cents
Col. A: \(3800 - 3420 = 380\)
Col. B: \(4180 - 3800 = 380\)
Hence, option C
We can solve this question without putting pen to paper - If we increase the price of an item by x% and decrease the price of the same item by x%, the difference between actual price and new price will always be x (which you can clearly notice in the above example where x = 10)
General Discussion
Re: A grocer buys apples at the regular price of 38 cents per pound.
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11 Jul 2021, 01:14
11 Jul 2021, 01:14
1
Solution:
Qty A: 100(0.38)-100(0.38-x)= 38-38+100x=100x
Qty B: 100(0.38+x)- 100(0.38)=38+100x-38=100x
Qty A=Qty B
IMO C
Hope this helps!
Qty A: 100(0.38)-100(0.38-x)= 38-38+100x=100x
Qty B: 100(0.38+x)- 100(0.38)=38+100x-38=100x
Qty A=Qty B
IMO C
Hope this helps!
