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A group of children start a mowing and raking team called Gardening Gu
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02 Aug 2021, 01:37
02 Aug 2021, 01:37
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A group of children start a mowing and raking team called Gardening Guys that services one neighborhood house a day for 21 days. Each day, Gardening Guys receives $50 for their services and divides it equally between all the children who serviced the house that day. For one week (7 days), 3 children on the team go to camp and can’t work on the team, but they work every day they are not in camp. Everyone else works on the team every day. If there are k total children in Gardening Guys, where k > 3, how much will Lamar, who does not go to camp, make from working on the team?
A. \(\frac{1050}{k(k-2)(k-3)}\)
B. \(\frac{1050k}{(k-3)}\)
C. \(\frac{1050(k-3)}{k(k-2)}\)
D. \(\frac{1050}{k(k-3)}\)
E. \(\frac{1050(k-2)}{k(k-3)}\)
A. \(\frac{1050}{k(k-2)(k-3)}\)
B. \(\frac{1050k}{(k-3)}\)
C. \(\frac{1050(k-3)}{k(k-2)}\)
D. \(\frac{1050}{k(k-3)}\)
E. \(\frac{1050(k-2)}{k(k-3)}\)
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Re: A group of children start a mowing and raking team called Gardening Gu
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04 Aug 2021, 07:53
04 Aug 2021, 07:53
2
GeminiHeat wrote:
A group of children start a mowing and raking team called Gardening Guys that services one neighborhood house a day for 21 days. Each day, Gardening Guys receives $50 for their services and divides it equally between all the children who serviced the house that day. For one week (7 days), 3 children on the team go to camp and can’t work on the team, but they work every day they are not in camp. Everyone else works on the team every day. If there are k total children in Gardening Guys, where k > 3, how much will Lamar, who does not go to camp, make from working on the team?
A. \(\frac{1050}{k(k-2)(k-3)}\)
B. \(\frac{1050k}{(k-3)}\)
C. \(\frac{1050(k-3)}{k(k-2)}\)
D. \(\frac{1050}{k(k-3)}\)
E. \(\frac{1050(k-2)}{k(k-3)}\)
A. \(\frac{1050}{k(k-2)(k-3)}\)
B. \(\frac{1050k}{(k-3)}\)
C. \(\frac{1050(k-3)}{k(k-2)}\)
D. \(\frac{1050}{k(k-3)}\)
E. \(\frac{1050(k-2)}{k(k-3)}\)
The easiest and fastest way to solve these word problems is to assume a number
Let \(k = 5\)
Total money earned = \(21(50) = $1050\)
For 14 days all 5 work, so each one receives \(14(\frac{50}{5}) = $140\)
For 7 days only 2 go to work, so each one receives \(7(\frac{50}{2}) = $175\)
So Lamar earned = \(140 + 175 = $315\)
Lets check the option choices;
A. \(\frac{1050}{k(k-2)(k-3)}\)
\(\frac{1050}{5(5-2)(5-3)} = $35\)
B. \(\frac{1050k}{(k-3)}\)
\(\frac{1050(5)}{(5-3)} = $2625\)
C. \(\frac{1050(k-3)}{k(k-2)}\)
\(\frac{1050(5-3)}{5(5-2)} = $140\)
D. \(\frac{1050}{k(k-3)}\)
\(\frac{1050}{5(5-3)} = $105\)
E. \(\frac{1050(k-2)}{k(k-3)}\)
\(\frac{1050(5-3)}{5(5-3)} = $315\)
Hence, option E
gmatclubot
Re: A group of children start a mowing and raking team called Gardening Gu [#permalink]
04 Aug 2021, 07:53
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