Re: A lottery game consists of the host removing one ball at a
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26 Jun 2020, 06:33
The total number of potential combinations of 3 balls being drawn (with order mattering):
10*9*8 = 720
(the first draw we have 10 potential balls to draw from, second draw we have 9 leftover balls, and last draw we have 8 to choose from)
The only way to get 24 is to draw these numbers:
9+8+7 =24
However, 9 8 and 7 can all be drawn in any order (ex. getting 7,9,8 is the same as 8,7,9)
There are 6 different orderings of how we can draw those 3 numbers (7,8,9 - 7,9,8 - 8,9,7 - 8,7,9 - 9,7,8 - 9,8,7) (with order mattering)
Thus the ratio of our desired outcome to total outcomes is 6/720 , which simplifies to 1/120 (Answer D)
* Can also not worry about the order in the calculation of total outcomes and divide 720 by 3!. Then we would have only 1 outcome that's desired (since order wouldn't matter) and we would once again get 1/120