Carcass wrote:
A machine is made up of two components, A and B. Each component either works or fails. The failure or non-failure of one component is independent of the failure or non-failure of the other component. The machine works if at least one of the components works.
If the probability that each component works is \(\frac{2}{3}\), what is the probability that the machine works?
A. \(\frac{1}{9}\)
B. \(\frac{4}{9}\)
C. \(\frac{1}{2}\)
D. \(\frac{2}{3}\)
E. \(\frac{8}{9}\)
Here,
The probability of the machine doesn't work = \(1- \frac{2}{3} = \frac{1}{3}\)
Probability that neither A nor B are working = \(\frac{1}{3} * \frac{1}{3} = \frac{1}{9}\)
Probability that machine works = \(1 - \frac{1}{9} = \frac{8}{9}\)