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Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
A number 4p25q is divisible by 4 and 9; where p and q
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23 Sep 2021, 00:32
23 Sep 2021, 00:32
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Question Stats:
50% (01:12) correct
50% (02:22) wrong based on 2 sessions
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A number \(4p25q\) is divisible by 4 and 9, where \(p\) and \(q\) are the thousands and units digits, respectively. What is the minimum value of \(pq\) ?
(A) \(1/8\)
(B) \(1/7\)
(C) \(1/6\)
(D) \(2/5\)
(E) \(5/2\)
Source: Manhattan Review, GMAT Question Bank
(A) \(1/8\)
(B) \(1/7\)
(C) \(1/6\)
(D) \(2/5\)
(E) \(5/2\)
Source: Manhattan Review, GMAT Question Bank
Re: A number 4p25q is divisible by 4 and 9; where p and q
[#permalink]
23 Sep 2021, 07:43
23 Sep 2021, 07:43
2
motion2020 wrote:
A number \(4p25q\) is divisible by 4 and 9, where \(p\) and \(q\) are the thousands and units digits, respectively. What is the minimum value of \(pq\) ?
(A) \(1/8\)
(B) \(1/7\)
(C) \(1/6\)
(D) \(2/5\)
(E) \(5/2\)
(A) \(1/8\)
(B) \(1/7\)
(C) \(1/6\)
(D) \(2/5\)
(E) \(5/2\)
For any number if last 2 digits are divisible by 4, then the number is also divisible by 4. Similarly if the sum of digits is divisible by 9, then the number is divisible by 9.
So for 4p25q, the only combination that fits are p =1 and q =6 or p =5 and q =2.
And former gives the minimum value of 41252. Answer is C)
gmatclubot
Re: A number 4p25q is divisible by 4 and 9; where p and q [#permalink]
23 Sep 2021, 07:43
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