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A number N^2 has 35 factor [#permalink]
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Greprep911 wrote:
motion2020
Is it some kind of a formula that you are using?


not really, \(N^2\) has 35 factors means that the power of N is the product of 7 and 5 or 35 and 1

next, we must subtract the previsouly added 1 from each of exponential factor: 7-1 and 5-1 or 35-1 and 1-1

we subtract 1 from each exponential factor, because the number of combinations existing to establish the number of factors for certain number is related as \(x=y^a*z^b \)and number of factors=\((a+1)*(b+1)\)

since, the number N is squared, we also divide the differences by 2: (7-1)/2 and (5-1)/2 or (35-1)/2 and (1-1)/2

finally, to find the number of factors for N we should repeat the same with the expression (looking like formula to one's fresh eye): (1+(7-1)/2)*(1+(5-1)/2) or (1+(35-1)/2)*(1+(1-1)/2) resulting in 12 and 18 respectively

hope this helps
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A number N^2 has 35 factor [#permalink]
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