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Achmed finds that by wearing different combinations of the jackets, sh
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28 Sep 2021, 09:28
28 Sep 2021, 09:28
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Achmed finds that by wearing different combinations of the jackets, shirts and pairs of trousers that he owns, he can make up 90 different outfits. If he owns 5 jackets and 3 pairs of trousers, how many shirts does he own?
A. 3
B. 6
C. 12
D. 18
E. 30
A. 3
B. 6
C. 12
D. 18
E. 30
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Achmed finds that by wearing different combinations of the jackets, sh
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28 Sep 2021, 09:48
28 Sep 2021, 09:48
Carcass wrote:
Achmed finds that by wearing different combinations of the jackets, shirts and pairs of trousers that he owns, he can make up 90 different outfits. If he owns 5 jackets and 3 pairs of trousers, how many shirts does he own?
A. 3
B. 6
C. 12
D. 18
E. 30
A. 3
B. 6
C. 12
D. 18
E. 30
If Achmed owns A jackets, B shirts and C pairs of trousers, then the Fundamental Counting Principle (FCP) tells us that the total number of outfits = ABC
In other words we get: ABC = 90 (different outfits)
Since we're told A = 5 and C = 3, we can plug these values into our equation (ABC = 90) to get: (5)(B)(3) = 90
Solve to get B =6
Answer: B
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Achmed finds that by wearing different combinations of the jackets, sh [#permalink]
28 Sep 2021, 09:48
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