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Joined: 10 Apr 2015
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At Mindy's restaurant, for every 4 people who ordered cheesecake, ther
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27 Oct 2021, 08:59
27 Oct 2021, 08:59
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Question Stats:
50% (00:35) correct
50% (01:20) wrong based on 8 sessions
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At Mindy's restaurant, for every 4 people who ordered cheesecake, there are 5 people who ordered strudel. If we let C represent the number of cheesecakes ordered, and let S represent the number of strudels ordered, which of the following equations must be correct?
A) \(C + S = 9\)
B) \(4C = 5S\)
C) \(\frac{4}{9}S = C\)
D) \(4+C = 5+S\)
E) \(5C = 4S\)
A) \(C + S = 9\)
B) \(4C = 5S\)
C) \(\frac{4}{9}S = C\)
D) \(4+C = 5+S\)
E) \(5C = 4S\)
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
At Mindy's restaurant, for every 4 people who ordered cheesecake, ther
[#permalink]
28 Oct 2021, 05:29
28 Oct 2021, 05:29
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GreenlightTestPrep wrote:
At Mindy's restaurant, for every 4 people who ordered cheesecake, there are 5 people who ordered strudel. If we let C represent the number of cheesecakes ordered, and let S represent the number of strudels ordered, which of the following equations must be correct?
A) \(C + S = 9\)
B) \(4C = 5S\)
C) \(\frac{4}{9}S = C\)
D) \(4+C = 5+S\)
E) \(5C = 4S\)
A) \(C + S = 9\)
B) \(4C = 5S\)
C) \(\frac{4}{9}S = C\)
D) \(4+C = 5+S\)
E) \(5C = 4S\)
Note: This question is from a popular study in mathematics education research: https://www.jstor.org/stable/748434
In the study, this question was posed to 150 first-year engineering students, and only 27% of the students were able to correctly answer it.
Given: For every 4 people who ordered cheesecake, there are 5 people who ordered strudel
In other words: (The number of cheesecake people)/(The number of strudel people) = 4/5
Substitute variables to get: C/S = 4/5
Cross multiply to get: 5C =4S
Answer: E
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At Mindy's restaurant, for every 4 people who ordered cheesecake, ther [#permalink]
28 Oct 2021, 05:29
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