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Bane had 3 different color paints with him - Red, Green, and Blue. He
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29 Sep 2021, 04:19
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Bane had 3 different color paints with him - Red, Green, and Blue. He wanted to paint a wall with 6 vertical stripes, but no two adjacent stripes could be of the same color. Assuming that Bane can use one color more than once, in how many ways can Bane paint the wall?
Re: Bane had 3 different color paints with him - Red, Green, and Blue. He
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29 Sep 2021, 05:16
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Carcass wrote:
Bane had 3 different color paints with him - Red, Green, and Blue. He wanted to paint a wall with 6 vertical stripes, but no two adjacent stripes could be of the same color. Assuming that Bane can use one color more than once, in how many ways can Bane paint the wall?
A. 32 B. 64 C. 96 D. 243 E. 729
Take the task of painting the 6 stripes and break it into stages.
Stage 1: Select a color for the first stripe Since we have 3 colors to choose from, we can complete stage 1 in 3 ways
Stage 2: Select a color for the 2nd stripe This stripe cannot be the same color as stripe #1. So, there are 2 remaining colors from which to choose, which means we can complete this stage in 2 ways.
Stage 3: Select a color for the 3rd stripe This stripe cannot be the same color as stripe #2. So, there are 2 remaining colors from which to choose, which means we can complete this stage in 2 ways.
Stage 4: Select a color for the 4th stripe Applying the logic we applied above, we can complete this stage in 2 ways
Stage 5: Select a color for the 5th stripe We can complete this stage in 2 ways
Stage 6: Select a color for the 6th stripe We can complete this stage in 2 ways.
By the Fundamental Counting Principle (FCP), we can complete all 6 stages (and thus paint all 6 stripes) in (3)(2)(2)(2)(2)(2) ways (= 96 ways)
Answer: C
Note: the FCP can be used to solve the MAJORITY of counting questions on the GRE. So, be sure to learn it.
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