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Not able to solve this question. Can anyone help?
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Updated on: 24 Apr 2020, 06:04
Updated on: 24 Apr 2020, 06:04
A certain experiment has only A, B and C as the possible outcomes. If A and B are mutually exclusive events and P(A or B)=0.7. If B and C are independent events and P(B and C)=0.2, P(A)=?
Re: Doubt in probability
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24 Apr 2020, 06:01
24 Apr 2020, 06:01
Expert Reply
Please post the question in its entirety
Or say us which is your doubt. So we can help you.
This way is not that clear
regards
Or say us which is your doubt. So we can help you.
This way is not that clear
regards
Re: Not able to solve this question. Can anyone help?
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06 Aug 2020, 00:17
06 Aug 2020, 00:17
vidit99 wrote:
A certain experiment has only A, B and C as the possible outcomes. If A and B are mutually exclusive events and P(A or B)=0.7. If B and C are independent events and P(B and C)=0.2, P(A)=?
Here's what's going on here
A and B are outcomes that can't happen together, which is what it means to be mutually exclusive. The combined probability of either one happening is .7, or 7/10
if there are only A, B, and C as outcomes then C is the other .3 or 3/10
the second half is giving you an opportunity to see what is the probability of outcome C by itself
to find the probability of two independent outcomes happening together, you just multiply them. So we know that C is 3/10 and the outcome is
2/10, so 3/10 X C = 2/10
which simplifies to C = 2/3
Now to find A we just have to find a common denominator and subtract C from the total of 7/10
easiest common denominator is 30, so (21/30) - (20/30) = 1/30
A = 1/30 By itself
Sorry for not using all the little codes to make stuff look like regular math, I haven't gotten the swing of it yet. Hope this helps
