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Each dimension of the rectangular solid pictured is an integ
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19 Mar 2019, 09:11
19 Mar 2019, 09:11
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#GREpracticequestion Each dimension of the rectangular solid.jpg [ 14.4 KiB | Viewed 1581 times ]
Each dimension of the rectangular solid pictured is an integer less than 6. Which of the following is the total surface area of the solid?
A. 24
B. 52
C. 60
D. 68
E. 78
MyGuru Representative
Joined: 09 Apr 2020
Posts: 35
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Re: Each dimension of the rectangular solid pictured is an integ
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13 Apr 2020, 16:22
13 Apr 2020, 16:22
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Expert Reply
Simplify the question first. We're given a volume of 24, and a width of 4. Since volume = length x width x height, we can divide the volume by 4 to get the product of the remaining two dimensions (length & height in the figure)
Since 4*length*height = 24, the product of the length and height is 6.
Now, let's look at the other information in the question:
1) Each dimension is an integer
2) Each dimension has to be less than 6
There's only one way for that to be true: that's if one dimension is 3 and the other is 2. (6 and 1 won't work, since 6 is NOT less than 6)
Now all that's left is to calculate the surface area, with the dimensions 2, 3, and 4.
2(2*3) + 2(3*4) + 2(2*4) = 12 + 24 + 16 = 52
Answer: B
Since 4*length*height = 24, the product of the length and height is 6.
Now, let's look at the other information in the question:
1) Each dimension is an integer
2) Each dimension has to be less than 6
There's only one way for that to be true: that's if one dimension is 3 and the other is 2. (6 and 1 won't work, since 6 is NOT less than 6)
Now all that's left is to calculate the surface area, with the dimensions 2, 3, and 4.
2(2*3) + 2(3*4) + 2(2*4) = 12 + 24 + 16 = 52
Answer: B
gmatclubot
Re: Each dimension of the rectangular solid pictured is an integ [#permalink]
13 Apr 2020, 16:22
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