Re: Each dimension of the rectangular solid pictured is an integ
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24 Apr 2018, 03:28
surface area of a cuboid is given by \(2(lb +lh + bh)\)
volume \(= l*b*h = 24\)
given b = 4 we can simply the volume as \(l*4 *h = 24\)
or, \(l*h = 6\)
therefore the two dimension must be \(2\) and \(3\) it does not matter whether length is \(2\) or height is \(2\)
Also notice that \(6\) and \(1\) may also be the dimension but question mentions that each dimension is less than \(6\)
now surface area \(= 2(8 + 12 + 6) =52\)
option B