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f (x) = x^2 + 2^x for all integers x. f (k)
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30 Nov 2023, 23:50
30 Nov 2023, 23:50
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\(f (x) = x^2 + 2^x\) for all integers x. \(f (k)=\frac{3}{2}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
k |
0 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Free Materials for the GRE General Exam - Where to get it!!
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f (x) = x^2 + 2^x for all integers x. f (k)
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01 Dec 2023, 19:05
01 Dec 2023, 19:05
1
When the comparison column is 0, I find that it is a good tactic to consider -1 and 1 as inputs for k, as well as when k = 0.
\(f(-1) = \frac{3}{2}\)
\(f(0) = 1\)
\(f(1) = 3\)
f(-1) gets us exactly one of the solutions. However, we can see there is also some value of k between 0 and 1 that would get us \(\frac{3}{2}\). (The exact value of this k isn't necessary to answer this question, just that it's greater than 0.)
Therefore, there are 2 solutions for k on both sides of 0, so the answer is D.
\(f(-1) = \frac{3}{2}\)
\(f(0) = 1\)
\(f(1) = 3\)
f(-1) gets us exactly one of the solutions. However, we can see there is also some value of k between 0 and 1 that would get us \(\frac{3}{2}\). (The exact value of this k isn't necessary to answer this question, just that it's greater than 0.)
Therefore, there are 2 solutions for k on both sides of 0, so the answer is D.
gmatclubot
f (x) = x^2 + 2^x for all integers x. f (k) [#permalink]
01 Dec 2023, 19:05
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