GeminiHeat wrote:
Five identical pieces of wire are soldered together end-to-end to form one longer wire, with the pieces overlapping by 4cm at each joint. If the wire thus made is exactly 1 meter long, how long, in centimeters, is each of the identical pieces?
(A) 21.2
(B) 22
(C) 23.2
(D) 24
(E) 25.4
Length of longer wire = 1m = 100cm
Without joints, each wire would be \(\frac{100}{5} = 20\)cm long
|---1---(O)---2---(O)---3---(O)---4---(O)---5---|
We will have 4 overlapping of 4cm each = 4(4) = 16cm
i.e. 16cm will be divided equally into 5 parts
So, each smaller wire is \(\frac{16}{5} = 3.2\)cm longer
Length of each small wire = 20 + 3.2 = 23.2cm
Hence, option C