In order for 130/x to be an integer, x must be a divisor of 130

So, the question is really asking us to determine the number of positive divisors of 130.
To do this, we can use the following rule:
If the prime factorization of N = (p^a)(q^b)(r^c) . . . (where p, q, r, etc are different prime numbers), then N has a total of (a+1)(b+1)(c+1)(etc) positive divisors.

Example: 14000 = (2^4)(5^3)(7^1)
So, the number of positive divisors of 14000 = (4+1)(3+1)(1+1) =(5)(4)(2) = 40

Now onto the question.......
130 = (2)(5)(13) = (2^1)(5^1)(13^1)
So, the number of positive divisors of 130 = (1+1)(1+1)(1+1) =(2)(2)(2) = 8

Answer: A