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Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Four terms in Arithmetic progression have a sum of 28.
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27 Aug 2021, 09:45
27 Aug 2021, 09:45
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Question Stats:
50% (03:24) correct
50% (01:37) wrong based on 16 sessions
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Four terms \(a, b, c,\) and \(d\) are in Arithmetic progression
\(a + b + c + d = 28\) and \(\frac{ad}{bc} = \frac{5}{6}\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
\(a + b + c + d = 28\) and \(\frac{ad}{bc} = \frac{5}{6}\)
Quantity A |
Quantity B |
\(d\) |
11 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Four terms in Arithmetic progression have a sum of 28.
[#permalink]
31 Aug 2021, 21:24
31 Aug 2021, 21:24
1
Explanation:
Let the terms be (x - 3), (x - 1), (x + 1), and (x + 3)
So, (x - 3) + (x- 1) + (x + 1) + (x + 3) = 28
x = 7
Therfore, terms are 4, 6, 8, and 10
Let us check if x = 7 satisfies the second scenario;
\(\frac{(4)(10)}{(6)(8)} = \frac{40}{48} = \frac{5}{6}\)
We have a match
Col. A: 10
Col. B: 11
Hence, option B
Let the terms be (x - 3), (x - 1), (x + 1), and (x + 3)
So, (x - 3) + (x- 1) + (x + 1) + (x + 3) = 28
x = 7
Therfore, terms are 4, 6, 8, and 10
Let us check if x = 7 satisfies the second scenario;
\(\frac{(4)(10)}{(6)(8)} = \frac{40}{48} = \frac{5}{6}\)
We have a match
Col. A: 10
Col. B: 11
Hence, option B
General Discussion
Re: Four terms in Arithmetic progression have a sum of 28.
[#permalink]
31 Aug 2021, 09:04
31 Aug 2021, 09:04
KarunMendiratta wrote:
Four terms \(a, b, c,\) and \(d\) are in Arithmetic progression
\(a + b + c + d = 28\) and \(\frac{ad}{bc} = \frac{5}{6}\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
\(a + b + c + d = 28\) and \(\frac{ad}{bc} = \frac{5}{6}\)
Quantity A |
Quantity B |
\(d\) |
11 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Solution please!
